ACT Math || SAT Math || Area on the Coordinate Plane || Practice Set
Area on the Coordinate Plane
Practice Set — Absolute Values, Circles & Inscribed Shapes
Instructions
- You may use scratch paper and a calculator where appropriate.
- Show all steps — for absolute-value regions, identify vertices or diagonals; for circles give radius/diameter; for inscribed shapes justify your geometry.
- Answers requiring \( \pi \) may be left in terms of \( \pi \).
Problems (1–15)
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What is the area, in square units, enclosed by
$$ y = -|x+4| + 7 \quad \text{and} \quad y = |x+4| - 5 $$
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What is the area of the region enclosed by
$$ y = 12 - |x-6| $$(Interpret the V-shape and the x-intercepts.)
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What is the area of the region described by
$$ |x-8| + |y-1| = 10 $$
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Find the area of the region enclosed by
$$ 3|x| + 2|y| = 18 $$
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What is the absolute difference between the lengths of the diagonals of the region
$$ 4|x-2| + |y+3| = 20 $$
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What is the area, in square units, enclosed by
$$ (x-4)^2 + (y-9)^2 = 25 $$Express your answer in terms of \( \pi \).
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The area enclosed by
$$ |x-a| + |y-2| = b $$is \(72\) square units. Find \(b\).
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If the region enclosed by
$$ 6|x+1| + 3|y-5| = k $$has area \(54\), find the value of \(k\).
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A circle is inscribed in the figure
$$ 7|x| + 24|y| = 84 $$What is the area of the circle? Express your answer as a common fraction in terms of \( \pi \).
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A square is inscribed in the circle
$$ (x-3)^2 + (y+4)^2 = 32 $$What is the area of the square?
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What is the area of the region enclosed by
$$ y = |x+10| - 3 \quad \text{and} \quad y = -|x+10| + 9 $$
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What is the area, in square units, of the region enclosed by
$$ |x-2| + 3|y| = 15 $$
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A diamond described by
$$ 2|x-1| + 5|y+6| = p $$has diagonals whose lengths differ by \(6\). Find \(p\).
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The graph
$$ (x+12)^2 + (y-1)^2 = 18 $$is a circle. What is the area of a regular hexagon inscribed in this circle?
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A rectangle is inscribed in the region
$$ |x| + |y| = 14 $$with its sides parallel to the coordinate axes. What is the maximum possible area of such a rectangle? Explain your reasoning.
Hints & Helpful Formulas
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For
\( |x-h| + |y-k| = R \),
the graph is a diamond (rotated square) whose area is
$$ 2R^2 $$
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For
\( a|x-h| + b|y-k| = c \),
the diagonals are
$$ d_x = \frac{2c}{a}, \qquad d_y = \frac{2c}{b} $$and area is$$ A = \frac{d_x d_y}{2} $$
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Distance from origin to line
\( Ax+By+C=0 \)
is
$$ \frac{|C|}{\sqrt{A^2+B^2}} $$
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Area of an inscribed square in a circle of radius
\(r\):
$$ A = 2r^2 $$
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Area of a regular hexagon inscribed in a circle of radius
\(r\):
$$ A = \frac{3\sqrt{3}}{2}r^2 $$
Use the hints if you get stuck, but show full steps in your written work.