ACT Math || SAT Math || Solution of Area on the Coordinate Plane (Questions published on Dec 8, 2025)
Area on the Coordinate Plane
Full Step-by-Step Solutions (Problems 1–15)
Working Conventions / Reminders
- For \( |x-h|+|y-k|=R \), the graph is a diamond with area \(2R^2\).
- For \( a|x-h| + b|y-k| = c \), diagonals are \(2c/a\) and \(2c/b\).
- Area of a circle: \(A=\pi r^2\).
Solutions
-
Problem 1
$$ y = -|x+4| + 7 $$$$ y = |x+4| - 5 $$Set equal:$$ -|x+4|+7 = |x+4|-5 $$$$ 12 = 2|x+4| $$$$ |x+4|=6 $$$$ x=-10,\ 2 $$$$ A=\frac{12\times12}{2}=72 $$$$ \boxed{72} $$
-
Problem 2
$$ y = 12-|x-6| $$Set \(y=0\):$$ 12-|x-6|=0 $$$$ |x-6|=12 $$$$ x=-6,\ 18 $$$$ A=\frac12(24)(12)=144 $$$$ \boxed{144} $$
-
Problem 3
$$ |x-8|+|y-1|=10 $$$$ A=2(10)^2=200 $$$$ \boxed{200} $$
-
Problem 4
$$ 3|x|+2|y|=18 $$$$ A=\frac{12\times18}{2}=108 $$$$ \boxed{108} $$
-
Problem 5
$$ 4|x-2|+|y+3|=20 $$$$ |40-10|=30 $$$$ \boxed{30} $$
-
Problem 6
$$ (x-4)^2+(y-9)^2=25 $$$$ A=25\pi $$$$ \boxed{25\pi} $$
-
Problem 7
$$ 2b^2=72 $$$$ b=6 $$$$ \boxed{6} $$
-
Problem 8
$$ 6|x+1|+3|y-5|=k $$$$ k=9\sqrt6 $$$$ \boxed{9\sqrt6} $$
-
Problem 9
$$ 7|x|+24|y|=84 $$$$ A=\frac{7056\pi}{625} $$$$ \boxed{\frac{7056\pi}{625}} $$
-
Problem 10
$$ (x-3)^2+(y+4)^2=32 $$$$ A=64 $$$$ \boxed{64} $$
-
Problem 11
$$ y = |x+10|-3 $$$$ y = -|x+10|+9 $$$$ A=\frac{12\times12}{2}=72 $$$$ \boxed{72} $$
-
Problem 12
$$ |x-2|+3|y|=15 $$$$ A=\frac{30\times10}{2}=150 $$$$ \boxed{150} $$
-
Problem 13
$$ 2|x-1|+5|y+6|=p $$$$ p=10 $$$$ \boxed{10} $$
-
Problem 14
$$ (x+12)^2+(y-1)^2=18 $$$$ A=27\sqrt3 $$$$ \boxed{27\sqrt3} $$
-
Problem 15
$$ |x|+|y|=14 $$$$ x=y=7 $$$$ A=196 $$$$ \boxed{196} $$
Quick Answers
- 72
- 144
- 200
- 108
- 30
- \(25\pi\)
- 6
- \(9\sqrt6\)
- \(\frac{7056\pi}{625}\)
- 64
- 72
- 150
- 10
- \(27\sqrt3\)
- 196